The CDBM CDBC is an 8-stage parallel input se- rial output shift register A parallel serial control input en- ables individual JAM inputs to each of 8 . Texas Instruments and its subsidiaries (TI) reserve the right to make changes to their products or to discontinue any product or service without notice, and advise . CD The an 8-stage parallel input serial output shift register A parallel serial control input enables individual JAM inputs to each of 8 stages Q outputs are.

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CD – Q8 output. According to the output table image CD – Q8 output. Is this not happening? The first one was wrong, the 8 input switches should be connected to VDD, not ground.

Have you hit all pins with a logic probe to make sure they have the voltage you think they do? All bets are off until you debounce the push button driving the clock input – you will be getting anything from 1 to hundreds of edges everytime you press it at the moment. PE – LOW 6. JoeN Edison Member Posts: Under these conditions, the chip does datashwet advance these 8 bits at all and SER IN is completely ignored.


I thought that the AVR has Schmitt trigger inputs when a port is configured for digital input. Basically I’m duplicating what a MCU does but at very slow speed.

I will never ask you to do anything that I wouldn’t do myself. Input s n – LOW 5.

CD4014 PDF Datasheet浏览和下载

MarkT Brattain Member Posts: Q7 goes into Q8. Input s n – HIGH I did this with one of the 8 inputs and in another test with two inputs simultaneously 3.

In either case, after the clock rises, Q6, Q7, and Q8 are available on their respective output pins. While doing the tests I wrote down the output state of Q8.

I’ve just updated the schematic image. That is what the data sheet says, at least. CDBE with buttons and leds. I’ve found some code online but unfortunately it is not helpful for understanding how the shift register works. Here is it in English.

CD Datasheet(PDF) – National Semiconductor (TI)

This is called a “preset” function. It looks like a weird serial-in, last-three-bits-out, with parallel 8 bit preset shift register to me. I read the truth table simply. MarkT on Oct 06, CD BE – Understanding the truth datxsheet.


JoeN on Oct 09, Data Sheet for the CD Datqsheet – truth table. Mechanical switches should never drive logic clocks directly for this reason!


I did this before with a 74HC shift register and it clarified for me how it functions, but with the CD it’s a different story. Here’s how I use the switches to duplicate what the MCU does: I’m not sure if this is the correct way to do it but I got some results that I don’t understand. What does Qn-1 do? What does Q1 Internal mean?